4x^2-48x-256=0

Solution for 4x^2-48x-256=0 equation:

4x^2-48x-256=0

a = 4; b = -48; c = -256;
Δ = b2-4ac
Δ = -482-4·4·(-256)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-80}{2*4}=\frac{-32}{8}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+80}{2*4}=\frac{128}{8}
=16
$